2[5-(2z+1)]-4=2(3-z)

Solution for 2[5-(2z+1)]-4=2(3-z) equation:

Simplifying
2[5 + -1(2z + 1)] + -4 = 2(3 + -1z)

Reorder the terms:
2[5 + -1(1 + 2z)] + -4 = 2(3 + -1z)
2[5 + (1 * -1 + 2z * -1)] + -4 = 2(3 + -1z)
2[5 + (-1 + -2z)] + -4 = 2(3 + -1z)

Combine like terms: 5 + -1 = 4
2[4 + -2z] + -4 = 2(3 + -1z)
[4 * 2 + -2z * 2] + -4 = 2(3 + -1z)
[8 + -4z] + -4 = 2(3 + -1z)

Reorder the terms:
8 + -4 + -4z = 2(3 + -1z)

Combine like terms: 8 + -4 = 4
4 + -4z = 2(3 + -1z)
4 + -4z = (3 * 2 + -1z * 2)
4 + -4z = (6 + -2z)

Solving
4 + -4z = 6 + -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
4 + -4z + 2z = 6 + -2z + 2z

Combine like terms: -4z + 2z = -2z
4 + -2z = 6 + -2z + 2z

Combine like terms: -2z + 2z = 0
4 + -2z = 6 + 0
4 + -2z = 6

Add '-4' to each side of the equation.
4 + -4 + -2z = 6 + -4

Combine like terms: 4 + -4 = 0
0 + -2z = 6 + -4
-2z = 6 + -4

Combine like terms: 6 + -4 = 2
-2z = 2

Divide each side by '-2'.
z = -1

Simplifying
z = -1